Newton-Raphson Method Calculator – Roots Fast
Newton iteration x←x−f(x)/f′(x) solves x²−2 from x₀=1: 1 → 1.5 → 1.4167 → 1.41422.
- Tangent-line steps and doubling digits shown.
Figures are estimates from this calculator’s standard formula — adjust the inputs in the tool below for your exact number.
How the Newton-Raphson Calculator Works
Newton’s method slides down the tangent line: at each guess xₖ it follows the tangent’s slope f′(xₖ) to where that tangent hits zero, which lands closer to the actual root. Solving f(x) = x² − 2 from x₀ = 1: the tangent update gives x₁ = 1 − (−1)/2 = 1.5, then x₂ = 1.41667, then x₃ = 1.41422 — √2 to five digits in three steps. Convergence is quadratic near a simple root: correct digits double each iteration (error 0.086 → 0.0025 → 0.0000031 in the run above). The calculator prints f and f′ at every iterate, the tangent step, and the residual, and warns about the failure modes — a zero derivative mid-run, or oscillation when the starting point sits far from the root on a curvy function (x₀ = −1 on this parabola bounces between −1 and 1; choosing x₀ = 2 fixes it). Compare slower but safer methods: bisection halves the interval every step.
- 1
Enter f(x) and f′(x)
The function and its derivative (or pick a preset)
- 2
Choose the starting guess
Close guesses converge fastest
- 3
Iterate the tangent step
Each xₖ, f(xₖ), f′(xₖ) and update is listed
- 4
Stop at tolerance
Run ends when |f(xₖ)| < your threshold
Use Cases
Root Finding
Solve x² − 2 = 0 to machine precision in 3–4 steps
Optimization
Set f′ = 0: Newton on the derivative finds maxima/minima
Financial Models
Iterate yield-to-maturity and implied volatility solutions
Tips
- 1
Quadratic convergence: digits double per step near a simple root
- 2
Each step costs one function plus one derivative evaluation
- 3
A derivative near zero stalls the method — pick another start
Common Mistakes
Using f′(x₀) for every step instead of recomputing f′(xₖ)
Starting far from the root on flat regions and diverging
Forgetting multiplicity: double roots converge only linearly
Skipping the residual check |f(x)| before accepting the answer
FAQs
How fast does Newton find √2?
Why is it called the tangent method?
When does Newton fail?
How does it compare with bisection?
Can Newton find maxima?
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