Simultaneous Equations Solver – 2×2 Systems
Solve two linear equations at once: 2x+y=5 and x−y=1 give x=2, y=1.
- Elimination steps and the determinant check for uniqueness included.
Figures are estimates from this calculator’s standard formula — adjust the inputs in the tool below for your exact number.
How the Simultaneous Equations Solver Works
A 2×2 linear system intersects two lines at a single point (usually). The solver uses elimination and prints every step for the system 2x + y = 5, x − y = 1: adding the equations removes y (3x = 6), giving x = 2, and back-substitution into either equation returns y = 1. Verification runs both ways: 2(2)+1 = 5 and 2−1 = 1. The determinant D = a₁b₂ − a₂b₁ = 2(−1) − 1(1) = −3 ≠ 0 certifies a unique solution; when D = 0 the lines are parallel (no solution) or identical (infinitely many), and the tool reports which. Substitution and Cramer’s rule solutions appear alongside, so the answer can be cross-checked three ways. Applications include break-even analysis, mixture problems, and Kirchhoff circuit pairs.
- 1
Enter both equations
Coefficients a, b, c for each of the two lines
- 2
Check the determinant
D = a₁b₂ − a₂b₁ — nonzero guarantees one solution
- 3
Eliminate and back-substitute
Each arithmetic step is displayed
- 4
Verify in both equations
The solution is substituted into each original line
Use Cases
Break-Even Analysis
Revenue 5x and cost 2x+90 intersect at x = 30 units
Mixture Problems
Blend 30%/60% solutions to a target concentration
Circuit Pairs
Two-loop Kirchhoff equations solve branch currents
Tips
- 1
D ≠ 0 ⇒ unique intersection; D = 0 ⇒ parallel or identical lines
- 2
Elimination targets the variable with equal-opposite coefficients
- 3
Always substitute the answer back into BOTH equations
Common Mistakes
Sign slips when adding equations to eliminate a variable
Solving for x and forgetting to back-substitute for y
Missing the D = 0 case and reporting a phantom solution
Mixing coefficient order between the two equations
FAQs
How do I solve 2x+y=5 and x−y=1?
When does a system have no solution?
What does determinant D = 0 mean here?
How do I verify (2,1)?
Can there be two solutions?
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