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Capacitor Energy Storage Calculator (J)

Quick answer

This calculator computes stored energy with E = CV2/2 for any capacitor or bank: enter capacitance and voltage for joules, watt-hours, and pulse capability.

Figures are estimates from this calculator’s standard formula — adjust the inputs in the tool below for your exact number.

How Does the Capacitor Energy Storage Calculator Work?

E = ½ × C × V²

Every capacitor stores energy proportional to capacitance and to voltage squared - doubling voltage quadruples the reserve. This calculator converts farads and volts into joules and watt-hours so different storage technologies compare fairly. Example: a 2200 uF DC-link capacitor at 400 V holds 176 J; delivering 500 W during a 0.1 s mains dip requires exactly 50 J, so one capacitor rides through ten cycles with margin. Banks add cell energies linearly whether series or parallel. Voltage window economics: because E scales with V squared, doubling bank voltage quadruples stored energy in the same capacitance, which is why EV DC links run at 400-800 V rather than 48 V.

  1. 1

    Enter capacitance

    In F, uF, or nF.

  2. 2

    Enter working voltage

    Charged volts.

  3. 3

    Read energy

    Joules, Wh, and pulse capability.

Use Cases

Sizing DC-link and hold-up capacitors for drives and PSUs

Comparing supercap banks against small batteries for buffering

Estimating pulse energy for spot welders and photoflash

Common Mistakes

  • Using peak instead of working voltage and overstating energy

  • Forgetting the usable window: you can only spend energy above the minimum operating voltage

  • Ignoring ESR losses that heat the capacitor on fast discharge

FAQs

How is capacitor energy calculated?

E = C x V2/2. A 1 F supercap at 2.7 V stores 3.65 J; a 100 uF film cap at 600 V stores 18 J. Voltage dominates because it enters squared.

How long can a capacitor hold its energy?

Self-discharge is slow for film and ceramic (hours to days) but meaningful for supercaps (days to weeks) and electrolytics (minutes). The load, not leakage, usually drains it first: a 1000 uF at 12 V feeding 10 mA lasts about one second.

Series or parallel - which stores more?

Same total energy: series raises voltage but divides capacitance; the squared voltage exactly cancels the divided C. Choose topology for voltage rating and balancing, not energy.

Why does my capacitor bank lose voltage so fast?

Self-discharge plus load: a 1 F bank at 12 V feeding a 10 mA standby circuit drops 1.2 V per 100 s, E = CVt relationships make small supercaps look empty within minutes under real loads.