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Collatz Conjecture Calculator – 3n+1 Steps

Quick answer

Trace the 3n+1 problem: 6 falls 6→3→10→5→16→8→4→2→1 in 8 steps; 27 needs 111 steps peaking at 9232.

  • Every hop listed, chart included.

Figures are estimates from this calculator’s standard formula — adjust the inputs in the tool below for your exact number.

How the Collatz Sequence Calculator Works

n even → n/2 | n odd → 3n + 1 | stop at 1

The Collatz process applies one of two rules forever: halve even numbers, triple-and-add-one to odd numbers. Every starting value ever tested eventually reaches 1, but nobody has proved this for all integers — the Collatz conjecture, open since 1937. Starting at 6: even, so 3; odd, so 10; then 5, 16, 8, 4, 2, 1 — eight steps, peak value 16. Starting at 27 the ride is wild: 111 steps and a maximum of 9,232 before collapsing to 1. The calculator lists every hop, the step count, the peak value, and a mini-chart of the trajectory. Total stopping times vary irregularly: 15 takes 17 steps, 16 only 4 (straight halving), and 41 takes 65. Entering 1 shows the terminal cycle 1 → 4 → 2 → 1, which the tool halts at by convention.

  1. 1

    Enter a starting number

    Any positive integer, e.g. 6 or 27

  2. 2

    Apply the parity rule

    Even → n/2; odd → 3n+1, with each hop printed

  3. 3

    Track steps and peak

    Count of steps and maximum value are reported

  4. 4

    Reach 1 and stop

    The sequence halts at the 4-2-1 cycle

Use Cases

Math Enrichment

Explore why 27 explodes to 9,232 before falling

Programming Exercises

Benchmark memoized vs naive Collatz step counters

Number Talks

Compare stopping times: 15 → 17 steps, 16 → 4 steps

Tips

  • 1

    Powers of 2 fall straight down: 16 → 8 → 4 → 2 → 1

  • 2

    27 is the classic long flight: 111 steps, peak 9,232

  • 3

    The conjecture remains unproven for all integers

Common Mistakes

  • Applying 3n+1 to even numbers — parity check comes first

  • Counting the starting number as a step

  • Forgetting the process only promises behavior for positive integers

  • Expecting stopping time to grow with n — 27 outruns many larger starts

FAQs

What happens starting from 6?

6 → 3 → 10 → 5 → 16 → 8 → 4 → 2 → 1: eight steps, peak 16.

Why is 27 famous?

It takes 111 steps and climbs to 9,232 before reaching 1.

Has the Collatz conjecture been proven?

No — verified astronomically far by computer, but open in general since 1937.

Which numbers fall fastest?

Powers of 2: 16 needs just 4 steps (16→8→4→2→1).

What ends the sequence?

The cycle 4 → 2 → 1; the calculator stops on first reaching 1.