Sum of Series Calculator – Arithmetic & Geometric
Series sums with formulas: Σk for n=100 is 5050, Σk² = n(n+1)(2n+1)/6 gives 14 at n=3, and geometric 1+½+¼+… = 2.
- Steps shown.
Figures are estimates from this calculator’s standard formula — adjust the inputs in the tool below for your exact number.
How the Sum of Series Calculator Works
Series come in families, each with a closed form. The arithmetic series 1+2+…+n sums to n(n+1)/2, so the first 100 integers total 100×101/2 = 5,050. Squares follow Σk² = n(n+1)(2n+1)/6: for n = 3 that is 3×4×7/6 = 14 (indeed 1+4+9 = 14). Geometric series a₁ + a₁r + a₁r² + … sum to a₁(rⁿ−1)/(r−1); for a₁ = 3, r = 2, n = 4 the total is 3×15 = 45. When |r| < 1 the infinite sum converges: 1 + ½ + ¼ + … = 1/(1−½) = 2. The calculator identifies which family your series belongs to, applies the matching formula with full substitution, and cross-checks by direct addition for small n. Partial sums are tabulated so the growth pattern (quadratic for Σk², exponential for geometric r > 1) is visible.
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Enter the series type and terms
Arithmetic, geometric, or a raw list of terms
- 2
Apply the closed form
The matching formula substitution is displayed
- 3
Cross-check by addition
Small n values are summed directly as verification
- 4
Test convergence
Geometric series report S∞ when |r| < 1
Use Cases
Gauss-Style Problems
Sum 1..100 = 5,050 and 1..365 = 66,795 instantly
Compound Totals
3+6+12+24 = 45 via the geometric form
Proof Practice
Verify Σk² = 14 for n = 3 before trusting the general case
Tips
- 1
Σk = n(n+1)/2 and Σk² = n(n+1)(2n+1)/6 cover integer series
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Geometric sums need r ≠ 1; r = 1 means n equal terms
- 3
Infinite geometric sums exist only for |r| < 1
Common Mistakes
Using n(n+1)/2 for squares — Σk² has its own (2n+1)/6 factor
Dividing by (1−r) when r > 1 for a finite sum; that form needs (r−1)
Summing a divergent series like 1+2+4+… to a finite "answer"
Off-by-one: summing to n−1 after miscounting terms
FAQs
What is 1+2+…+100?
What is 1²+2²+3²?
What is 1+½+¼+…?
What is 3+6+12+24?
Does every infinite series converge?
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