Skip to main content

Complex Number Calculator – Arithmetic & Modulus

Quick answer

Operate on a+bi: (1+2i)(3+i)=1+7i, |3+4i|=5, conjugate 3−4i.

  • Add, subtract, multiply, divide with rectangular working shown.

Figures are estimates from this calculator’s standard formula — adjust the inputs in the tool below for your exact number.

How the Complex Number Calculator Works

(a+bi)(c+di) = (ac−bd) + (ad+bc)i | |a+bi| = √(a²+b²)

Complex numbers pair a real part with an imaginary part, and arithmetic follows i² = −1. Adding is component-wise: (3+2i) + (1−4i) = 4−2i. Multiplying distributes and swaps signs: (1+2i)(3+i) = 3 + i + 6i + 2i² = 3 + 7i − 2 = 1+7i. The conjugate flips the imaginary sign, and z × z̄ = |z|²: (3+4i)(3−4i) = 25, so |3+4i| = 5 — the distance from the origin in the complex plane. Division multiplies by the conjugate of the denominator, converting (1+2i)/(3−4i) into (−5+10i)/25 = −0.2+0.4i. The calculator prints each intermediate product and the modulus/argument pair, linking rectangular work to the geometry: the argument of 3+4i is arctan(4/3) ≈ 53.13°. Results stay exact in fraction form where possible.

  1. 1

    Enter two complex numbers

    Form a+bi for each, e.g. 1+2i and 3+i

  2. 2

    Pick the operation

    Add, subtract, multiply or divide

  3. 3

    Follow the distribution

    Every cross-product is shown, applying i² = −1

  4. 4

    Read modulus & argument

    |z| and θ = atan(b/a) accompany each result

Use Cases

AC Circuit Analysis

Impedances combine like complex numbers: Z = R + i(X_L − X_C)

Fractal Generation

Mandelbrot iteration z → z² + c needs fast complex products

Signal Processing

Phasors rotate via multiplication by e^{iθ}

Tips

  • 1

    i² = −1 is the only new rule; everything else is algebra

  • 2

    Multiply by the conjugate to divide complex numbers

  • 3

    z·z̄ = |z|², so |3+4i| = 5 without touching square roots

Common Mistakes

  • Writing i² as +1 instead of −1

  • Adding real to imaginary parts directly: (3+2i)+(1+4i) is 4+6i, components stay separate

  • Forgetting the conjugate when dividing, leaving i in the denominator

  • Computing modulus as a+b instead of √(a²+b²)

FAQs

What is (1+2i)(3+i)?

3 + i + 6i + 2i² = 1+7i after i² = −1.

What is |3+4i|?

√(9+16) = 5 — the distance to the origin in the complex plane.

How do I divide (1+2i)/(3−4i)?

Multiply by the conjugate: (1+2i)(3+4i)/25 = (−5+10i)/25 = −0.2+0.4i.

What is the conjugate of 3+4i?

3−4i; their product is the real number 25.

What is (3+2i)+(1−4i)?

4−2i — add real parts and imaginary parts separately.