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Riemann Sum Calculator – Left, Right & Midpoint

Quick answer

Approximate ∫ with rectangles: ∫₀¹x²dx with n=4 right endpoints gives 0.46875 vs exact 1/3; left gives 0.21875; midpoint 0.328125.

  • Tables shown.

Figures are estimates from this calculator’s standard formula — adjust the inputs in the tool below for your exact number.

How the Riemann Sum Calculator Works

Σ f(xₖ*)·Δx with Δx = (b−a)/n and xₖ* the left, right, or midpoint sample

A Riemann sum chops [a, b] into n rectangles of width Δx and adds their heights. For ∫₀¹ x² dx with n = 4: Δx = 0.25, and the right endpoints 0.25, 0.5, 0.75, 1 give heights 0.0625, 0.25, 0.5625, 1 — sum 1.875, times 0.25 = 0.46875, overshooting the exact 1/3 because x² rises. Left endpoints (0, 0.25, 0.5, 0.75) give 0.21875, an equal-footing underestimate; midpoint sampling (0.125, 0.375, 0.625, 0.875) gives 0.328125, already within 1.6% of 1/3. The calculator tabulates every rectangle, compares the three sampling rules, and shows the convergence as n grows — at n = 100 the midpoint rule lands within 0.00002. The left/right bracket [underestimate, overestimate] for monotone functions doubles as a rigorous error bound, and the sum itself is the definition of the definite integral in the limit n → ∞.

  1. 1

    Enter f(x), a, b, and n

    The integrand, bounds, and rectangle count

  2. 2

    Pick the sampling rule

    Left, right, or midpoint heights

  3. 3

    Build the table

    Each rectangle’s xₖ*, height, and area is listed

  4. 4

    Compare and converge

    All three rules plus the exact value when known

Use Cases

Calculus Introduction

Watch rectangles morph into the integral 1/3

Error Bounding

Left/right sums bracket monotone integrals

Data Integration

Totalize rates known at discrete times

Tips

  • 1

    Rising functions: left sum underestimates, right overestimates

  • 2

    Midpoint errors are about a quarter of trapezoid errors

  • 3

    The integral is defined as the n → ∞ limit of these sums

Common Mistakes

  • Using (b−a)/n with n+1 points and off-by-one widths

  • Sampling at interval edges for the midpoint rule

  • Forgetting the final multiplication by Δx

  • Averaging left and right and calling it midpoint — that is the trapezoid rule

FAQs

What is the right-endpoint estimate of ∫₀¹x² with n=4?

0.25×(0.0625+0.25+0.5625+1) = 0.46875, versus the exact 1/3.

And the left-endpoint sum?

0.25×(0+0.0625+0.25+0.5625) = 0.21875 — the matching underestimate.

Why is midpoint better?

0.328125 at n = 4, within 1.6%: midpoint errors cancel curvature to first order.

How do left/right sums bound the answer?

For monotone f the true integral lies between them: 0.21875 < 1/3 < 0.46875.

What happens as n → ∞?

All sampling rules converge to the integral — that limit is its definition.