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2x2 Matrix Inverse Calculator with Steps

Quick answer

Inverse = (1/det)[[d,−b],[−c,a]]: [[4,7],[2,6]] has det 10, so A⁻¹ = [[0.6,−0.7],[−0.2,0.4]].

  • Verification A·A⁻¹ = I included.

Figures are estimates from this calculator’s standard formula — adjust the inputs in the tool below for your exact number.

How the 2x2 Inverse Calculator Works

A⁻¹ = (1/(ad−bc))·[[d, −b], [−c, a]]

Inverting a 2×2 matrix swaps the main diagonal, negates the off-diagonal, and divides by the determinant. For A = [[4,7],[2,6]]: det = 4×6 − 7×2 = 10, so A⁻¹ = (1/10)[[6,−7],[−2,4]] = [[0.6,−0.7],[−0.2,0.4]]. Multiplying back verifies: A·A⁻¹ = [[1,0],[0,1]] to full precision — the calculator performs this check on every run. Zero determinant aborts with a singular-matrix explanation (row dependence means no undo exists). The tool outputs fractions and decimals side by side (here 3/5 and −7/10), connects to systems solving: [[4,7],[2,6]]x = b solves as x = A⁻¹b, and notes the geometric effect — this inverse maps areas by 1/10 and undoes the original shear-and-scale. The determinant of the inverse equals 1/det(A) = 0.1.

  1. 1

    Enter a, b, c, d

    The four entries of your matrix

  2. 2

    Compute the determinant

    ad − bc = 10 here; zero flags singular

  3. 3

    Swap and negate

    [[d,−b],[−c,a]] = [[6,−7],[−2,4]]

  4. 4

    Divide and verify

    Scale by 1/det; A·A⁻¹ = I is confirmed

Use Cases

Solving Linear Systems

x = A⁻¹b solves 4x+7y = b₁, 2x+6y = b₂ in one step

Graphics Transforms

Undo rotations/scalings by applying the inverse

Homework Checking

Fraction and decimal forms for exact grading

Tips

  • 1

    Swap the diagonal, negate the wings, divide by det

  • 2

    det = 0 ⇒ no inverse exists

  • 3

    det(A⁻¹) = 1/det(A)

Common Mistakes

  • Negating the diagonal instead of the off-diagonal

  • Forgetting to divide by the determinant

  • Applying the formula to singular matrices (det 0)

  • Mixing entry order when typing the matrix

FAQs

What is the inverse of [[4,7],[2,6]]?

(1/10)[[6,−7],[−2,4]] = [[0.6,−0.7],[−0.2,0.4]].

How is the result verified?

Multiply A·A⁻¹ — the identity [[1,0],[0,1]] returns.

What if det = 0?

No inverse: the matrix collapses the plane and cannot be undone.

What is det(A⁻¹) here?

1/10 = 0.1, the reciprocal of the original determinant.

How does this solve systems?

For [[4,7],[2,6]]x = [10, 6]: x = A⁻¹[10,6] = [1.8, 0.4].