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Geometric Sequence Calculator – nth Term & Sum

Quick answer

aₙ=a₁·rⁿ⁻¹ and Sₙ=a₁(rⁿ−1)/(r−1).

  • For 3,6,12,… with r=2: a₁₀=1536 and S₁₀=3069, plus infinite sum a₁/(1−r) when |r|<1.
  • Free.

Figures are estimates from this calculator’s standard formula — adjust the inputs in the tool below for your exact number.

How the Geometric Sequence Calculator Works

aₙ = a₁·rⁿ⁻¹ | Sₙ = a₁(rⁿ − 1)/(r − 1) | S∞ = a₁/(1−r), |r| < 1

Geometric sequences grow by multiplication, and the calculator exposes both directions. For 3, 6, 12, 24, …: a₁ = 3 and r = 2, so the 10th term is a₁₀ = 3×2⁹ = 3×512 = 1536 and the ten-term sum is S₁₀ = 3(2¹⁰−1)/(2−1) = 3×1023 = 3069. Give it scattered terms instead — a₂ = 6 and a₅ = 48 — and it recovers r³ = 8, r = 2, a₁ = 3 and rebuilds the list. When |r| < 1 the infinite sum converges: for 8 + 4 + 2 + … the total is a₁/(1−r) = 8/0.5 = 16, the math behind repeating decimals like 0.999… = 1. The tool prints each power of r, warns when |r| ≥ 1 makes S∞ diverge, and switches to scientific notation when terms explode past a₂₀.

  1. 1

    Enter a₁ and r

    Or provide two terms; the ratio is solved automatically

  2. 2

    Pick the term index

    aₙ = a₁·rⁿ⁻¹ is evaluated with each power of r shown

  3. 3

    Sum the first n terms

    Sₙ = a₁(rⁿ−1)/(r−1) — a special note appears for r = 1

  4. 4

    Check convergence

    If |r| < 1, the infinite sum a₁/(1−r) is reported

Use Cases

Investment Growth

2,000 at 8%/year: a₁₀ = 2000×1.08⁹ ≈ 3,998

Population Models

Bacteria doubling each hour: 10 cells reach 10×2⁶ = 640 in 6 hours

Signal Decay

Amp gain halving per stage: outputs 8, 4, 2, 1 mV total 15.99…≈16 mV

Tips

  • 1

    r = 1 is the degenerate case: every term equals a₁ and Sₙ = n·a₁

  • 2

    |r| < 1 converges; |r| ≥ 1 infinite sums do not exist

  • 3

    Compound interest is just a geometric sequence with r = 1 + rate

Common Mistakes

  • Raising r to n instead of n−1, doubling the 10th term of 3,6,12,… to 3072

  • Dividing by (1−r) when r > 1, where the finite formula needs (r−1)

  • Calling 2, 4, 6, 8 geometric — constant difference means arithmetic

  • Summing infinite series with r = −2, which oscillates and diverges

FAQs

What is the 10th term of 3, 6, 12, …?

a₁₀ = 3×2⁹ = 1536. The exponent is 9 because a₁ already covers r⁰.

What is the sum of the first 10 terms?

S₁₀ = 3(2¹⁰−1)/(2−1) = 3×1023 = 3069.

How do I find r from a₂ = 6 and a₅ = 48?

a₅/a₂ = r³ = 8, so r = 2 and a₁ = 6/2 = 3.

What is 8 + 4 + 2 + 1 + …?

r = 1/2, so S∞ = 8/(1−1/2) = 16 — a convergent infinite series.

What if r = 1?

The sum formula divides by zero; a constant sequence sums to n×a₁, e.g. 5+5+5 = 15.